Example
Ex 1:

Solve

Sol:
Ex 2:

Solve ,

Sol:
Given  ,
let  = p and q =
2p + 6q = 2 ..... (1)
3p – 2q = 4 ...... (2)
Multiply eq(1) by 3 and eq(2) by 2, we get
q = – 11
Substituting these value in equation (2)
3p – 2(– 11) = 4
3p + 22 = 4
3p = – 18
p = – 6
Substituting p and q values,
 = (1/–6),  = (1/–11)
(1/x) = (1/36), (1/y) = (1/121)
∴ x = 36, y = 121
Ex 3:

Solve (a + b)x + (a – b)y = a2 + b2, (a – b)(x + y) = a2 – b2

Sol:
Given (a + b)x + (a – b)y = a2 + b2 ..... (1)
(a – b)(x + y) = a2 – b2 ...... (2)
(a + b)x + (a – b)y – (a – b)x – (a – b)y = a2 + b2 – a2 + b2
(a + b – a + b)x = 2b2
∴ x = b
(a + b)b + (a – b)y = a2 + b2
ab + b2 + (a – b)y = a2 + b2
(a – b)y = a2 – ab
(a – b)y = a(a – ab)
∴ y = a
Ex 4:

3x + 7y = 25 , 5x – 5y = 25. find the xy + yx

Sol:
5x = 25 + 5(1) = 25 + 5
5x = 30
x = 30/5 = 6
xy + yx = 61 + 16
= 6 + 1 = 7
Ex 5:

2a + 3b = 17 , 2a + 2 – 3b + 1 = 5

Sol:

let 2a be x and 3b be y 2a + 3b = 17 , (2a × 22) – (3b × 31) = 5

x + y = 17
(x × 4) – (y × 3) = 5
4x - 3y = 5
x = 17 – 9 = 8
2a = 8
2a = 23
a = 3
3b = 9
3b = 32
b = 2
Ex 6:

Sol: