Examples
Ex:

Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.

Sol:
A circle with centre O touches the sides AB, BC, CD and DA of a quadrilateral ABCD at P, Q, R and S, respectively
∠1 = ∠2, ∠3 = ∠4, ∠5 = ∠6, ∠7 = ∠8
Since the sum of all the angles subtended at a point is 360°
∠1 + ∠2 + ∠3 + ∠4 + ∠5 + ∠6 + ∠7 + ∠8 = 360°
2∠2 + 2∠3 + 2∠6 + 2∠7 = 360°
2(∠2 + ∠3 + ∠6 + ∠7) = 360°
∠2 + ∠3 + ∠6 + ∠7 = 180°
(∠6 + ∠7) + (∠2 + ∠3) = 180°
∠AOB + ∠COD = 180°
Similarly, we can prove ∠AOD + ∠BOC 180°