Upthrust
1.

A solid weighs 55 gf in air and 49 gf when completely immersed in water. Calculate:
(i) The upthrust
(ii) The volume of the solid
(iii) The relative density of the solid

Sol:
(i) Upthrust = loss in weight
= 55−49
= 6 gf
(ii) Weight of water displaced = upthrust
= 6 gf
Since the density of water is 1 g cm−3,
∴ volume of water displaced = 6 cm3
But the solid displaces water equal to its own volume,
∴ volume of solid = 6 cm3
(iii) R.D. of solid = (Weight of solids in air) / (Weight in air – Weight in water)
= (55) / (55 – 49)
= 55/6
= 8.33
2.

A metal cube of side 7 cm and density 7.9 g cm–3 is suspended by a thread and is immersed completely in a liquid of density 1.1 g cm–3. Find the tension in the thread?

Sol:
Volume of the cube = 7 × 7 × 7 = 343 cm3
Mass of the cube = Volume × density
= 343 cm3 × 7.9 g cm–3
= 2709.7 g.
∴ Weight of the cube = 2709.7 gf (downwards)
Upthrust on cube = Weight of liquid displaced
= Volume of cube × density of liquid
= 343 × 1.1 gf = 377.3 gf (upwards)
∴ Tension in the thread = Net downward force
= Weight of cube − Upthrust on cube
= 2709.7 − 377.3
= 2332.4 gf
3.

A body weighs 240 gf in air and 230 gf when completely immersed in water. Calculate:
(i) The loss in weight of the body
(ii) The upthrust on the body

Sol:
Weight in air = 240 gf
Weight in water = 230 gf
(i) Loss in weight of the body = 240 gf − 230 gf
= 10 gf
(ii) Upthrust on the body = loss in weight
= 10 gf