We know that:
sinh^–1 x = log(x + ),
cosh^–1 x = log(x + ) and
tanh^–1 x =
It can be proved that:

i) (sinh–1 x) =	ii) (cosh–1 x) =
iii) (tanh–1 x) =	iv) (coth–1 x) =
v) (cosech–1 x) =	vi) (sech–1 x) =

Did you note that the derivatives of tanh^–1 x and coth^–1 x are the same?
(Their domains are disjoint though).
Most of the times, the domain is not explicitly stated.
We find the derivative in its appropriate domain.